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用python實現一個極簡的stack和queue,那是so easy的事情了,簡潔易懂,適合小白~
直接上代碼吧:
node:
class LinkNode: def __init__( self, value ): self.value = value self.next = None
stack:
class Stack: def __init__( self ): self.top = None def peek( self ): if not self.top: return None return self.top.value def is_empty( self ): return self.top == None def pop( self ): if not self.top: return None old_top = self.top self.top = self.top.next return old_top.value def push( self, value ): node = LinkNode( value ) node.next = self.top self.top = node
queue:
class Queue: def __init__( self ): self.first = None self.last = None def is_empty( self ): return self.last == None def dequeue( self ): if not self.first: return None old_first = self.first self.first = self.first.next if not self.first: self.last = None return old_first.value def enqueue( self, value ): node = LinkNode( value ) if not self.last: self.first = node self.last = node else: self.last.next = node self.last = node
test case:
# ''' # Stack test case # ''' s = Stack() s.push( 1 ) s.push( 0 ) s.push( -1 ) s.push( -1 ) s.push( 6 ) print( s.peek() ) s.pop() print( s.peek() ) s.pop() s.pop() s.pop() print( s.peek() ) s.pop() print( s.top ) # ''' # Queue test case # ''' q = Queue() q.enqueue( 1 ) q.enqueue( 2 ) q.enqueue( 0 ) q.enqueue( -1 ) q.enqueue( 8 ) q.dequeue() q.dequeue() q.dequeue() q.dequeue() print( q.first.value )
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